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12x^2+11x+2-5=0
We add all the numbers together, and all the variables
12x^2+11x-3=0
a = 12; b = 11; c = -3;
Δ = b2-4ac
Δ = 112-4·12·(-3)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{265}}{2*12}=\frac{-11-\sqrt{265}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{265}}{2*12}=\frac{-11+\sqrt{265}}{24} $
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